We know that they are both heterozygous, so what would be the genotypes for both parents?

Now that you have the genotypes of the parents, perform a punnett square to determine what the F₁ offspring would be (remember to place the gametes of one parent across the top and the gametes of the other parent down the left side. It does not matter which parent's gametes are placed across the top and which are placed down the side.):

Your punnett square should look similar to the one below. If it does not, review the material on gamete formation and how to set up the punnett square and try again.

Now count up how many of each genotype and each phenotype are in the four possible offspring.

Return to the question page to select the correct answers.