First determine what you know about the genotypes of the male's parents. One is short tailed and so must be homozygous recessive (ll). The other parent is long-tailed so what do we know about its genotype?




Because the male is long-tailed, he must have at least one dominant allele and that this allele came from his long-tailed parent. If the other parent is homozygous recessive, what then must the male's genotype be?




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OK, we know that the female grackle has a genotype of ll and the male a genotype of Ll. To find out the genotypes and phenotypes of the F1 generation, you need to perform a punnett square. Below is a blank square. Remember to place the gametes of one parent across the top and the gametes of the other parent down the left side. It does not matter which parent's gametes are placed across the top and which are placed down the side.





Your punnett square should look similar to the one below. If it does not, review the material on gamete formation and how to set up the punnett square and try again.

L l
l Ll ll
l Ll ll


Now count up how many of each genotype and how many of each phenotype you have.




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